РЕШЕНИЕ:
(x−2)2(x−3)=12(x−2)
(x−2)2(x−3) − 12(x−2) = 0
(x−2) ((х-2)(x−3) - 12) = 0
(х-2)(х2 - 2х - 3х + 6 - 12) = 0
(х-2)(х2 - 5х - 6) = 0
х-2 = 0 или х2 - 5х - 6 = 0
х = 2 или D = (-5)2 - 4∙1∙(-6) = 25 + 24 = 49 = 72
х = 2 или x1 = (5 + 7)/2 = 12/2 = 6 ; x2 = (5 - 7)/2 = - 2/2 = - 1 ;
Ответ: 2; 6 ; - 1