РЕШЕНИЕ:
___− 11___ ≥ 0
(x−2)2−3
(x−2)2−3 < 0
x2 – 4x + 4 – 3 < 0
x2 – 4x + 1 < 0
x2 – 4x + 1 = 0
D = 16 – 4∙1∙1 = 16 – 4 = 12 = 3∙4 = (2√3)2
x1 = (4 + 2√3) / 2 = 2 + √3
x2 = ( 4 – 2√3) / 2 = 2 – √3
____ + ________ – _________ +
_________o___________o________
______ 2 – √3_____ 2 + √3
Ответ: ( 2 – √3 ; 2 + √3)