РЕШЕНИЕ:
(x2−25)2+(x2 + 3x−10)2=0
x2 + 3x − 10 = 0
D = 32 - 4∙1∙(-10) = 9 + 40 = 49 = 72
x1 = (- 3 + 7) / 2 = 4/2 = 2
x1 = (- 3 - 7) / 2 = - 10/2 = -5
x2+3x−10 = (x+5)(x-2)
(x2−25)2+(x2 + 3x−10)2=0
((x-5)(x+5))2+(x+5)2 (x-5)2=0
(x-5)2(x+5)2 +(x+5)2 (x-2)2=0
(x+5)2((x-5)2 +(x-2)2)=0
(x-5)2 +(x-2)2 ≠ 0
x+5 = 0
x = - 5
Ответ: - 5